[完善]tab关闭和切换tab操作

src/module/tab/index.vue

@@ -1,8 +1,8 @@
 <template>
-  <div class="layui-tab" :class="[type ? 'layui-tab-' + type : '']">
+  <div class="layui-tab" :class="[type ? 'layui-tab-' + type : '']" v-if="active">
     <ul class="layui-tab-title">
       <li
-        v-for="children in childrens"
+        v-for="(children, index) in childrens"
         :key="children"
         :class="[children.props.id === active ? 'layui-this' : '']"
         @click.stop="change(children.props.id)"
@@ -11,7 +11,7 @@
         <i
           v-if="allowClose"
           class="layui-icon layui-icon-close layui-unselect layui-tab-close"
-          @click.stop="close(children.props.id)"
+          @click.stop="close(index, children.props.id)"
         ></i>
       </li>
     </ul>
@@ -60,6 +60,8 @@ const props = defineProps<{
   type?: string
   modelValue: string
   allowClose?: boolean
+  beforeClose?: Function
+  beforeLeave?: Function
 }>()
 
 const emit = defineEmits(['update:modelValue', 'change', 'close'])
@@ -75,11 +77,27 @@ const active = computed({
 const slotsChange = ref(true)
 
 const change = function (id: any) {
+  // 回调切换标签之前的回调钩子函数，只要不是return false, 则进行切换该tab
+  if (props.beforeLeave && props.beforeLeave(id) === false) {
+    return ;
+  }
   emit('update:modelValue', id)
   emit('change', id)
 }
 
-const close = function (id: any) {
+const close = function (index : number, id: any) {
+  // 回调关闭之前的回调函数，只要不是return false, 则进行关闭该tab
+  if (props.beforeClose && props.beforeClose(id) === false) {
+    return ;
+  }
+
+  // 删除当前tab
+  childrens.value.splice(index, 1);
+  // 点击的是当前激活的tab，则需要切换到下一个tab
+  if (active.value === id) {
+    const nextChildren = childrens.value[(index === childrens.value.length ? 0 : index)];
+    change(nextChildren && nextChildren.props ? nextChildren.props.id : "")
+  }
   emit('close', id)
 }